With no friction from the atmosphere, conservation of energy says that a bullet goes up with kinetic energy KE=1/2 mv^2 at the top of the trajectory that energy is stored as potential energy PE=mgh, and when it comes down, it has as much energy as it started out with. So when it is at the same height as it started out with (effectively the ground), it is going down as fast as it started out going up with. Now with drag, let's say terminal velocity is twice what a human body is. (It is probably a lot larger, as a bullet is denser and approximates a sphere better than a human body.) 200mph=about 100m/s. I don't want to be hit by a bullet going that fast, thanks. How much does a bullet weigh? That's quite some kinetic energy. And BTW, every year there are reports in the news about people getting killed by falling bullets. A .38 will do, no need for sexual chocolate's bazooka.