G-spotter

at the risk of thread-drift, when did these events occur, drew? up by Salal Ck? cheers, First off the main Plinth lava flow that created Keyhole Falls, and dates to 2350 BP (before present) Second of all the Capricorn Creek and Devastator (No Good Creek) drainages have both produced slides resulting in blockages of Meager Creek and generating flood waves down the Lillooet. None of the historic ones have reached Pemberton townsite as significant floods, most fizzled out at Pemberton Meadows. The Neal Carter party that made FAs of these peaks in the 30s were able to travel up the floodplain of the Lillooet to the Meager Group in style partly because it had been scoured by such a wave a few years earlier. Prehistoric evidence (sediment cores from Lillooet Lake) indicate that these flood waves recur every few hundred years at a size large enough to reach Pemberton townsite. We're overdue for a new one, BTW.

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So did some bears partially eat the body and then stash it in a tree?

There you go, it's just like a natural phenomenon, only bigger

What a COP OUT

Left, or right? It's with you, Dru. Don't you remember? So lube up and bend over. I'll be there in an hour... Sorry, I'm not Catholic.

Left, or right?

Please explain. I was previously led to believe that only the 30-60 and 45-45 triangles can be calculated from knowledge of the length of 1 side. Otherwise 2 sides were necessary and thus the angle irrelevant. Ken, Yes, the 30/60/90 and 45/45/90 triangles make it very easy to calculate the length of any side knowing only the length of one side. But that is not the problem statement here. Trigonometry says that you can solve for the length of any side of a right triangle knowing either 1) the lengths of the other two sides (by using Pythagorean Theorem), or 2) the length of one side and the value of one of the other two angles (those that are not the right angle). Since we are given the (overhanging) angle of the subject pitch of the Leaning Tower as 110 degrees, we know the interior of that angle is 70 degrees. And since the 200-foot side is known, and that side must be perpendicular to the ground line, we have all that is needed to solve by trig (one known side and two known angles). Now that we are on page 3, maybe it's time to point out that he's actually closer than 72.7 feet to the wall at the end of his line. Just not horizontally. Perpendicular distance from the wall = 72.8 * sin 70 = 68.4 feet from the wall at the end of his rope.

Aside from the b/w screen this sporty red number should meet all your requirements.

Same thing happened to Pemberton twice when landslides occurred on Meager... and blocked the Lillooet river.

"I'm too sexy for your bank, too sexy for your bank, oooh, too sexy..."

5.11: the grade young climbers give a 5.9 they can't do

if the guidebook says 9+ you should be expecting 10c.

If you want to trundle responsibly do it in the alpine after approaching from below.

you gotta date next tuesday, lebowski

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Remember how fast Patagucci dumped Dean Potter after the delicate arch stunt?

35% of dolphin sex is gay sex

To be clear: find a live, injured person? call for help, administer first aid find a dead person? rob the body, move on, call in when convenient.

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the right angle is between the horizontal and vertical so you are hanging straight down on a 200 ft rope, then (180-110) = 70 so tan 70 = opposite/adjacent = 200/x Solve for x = 200/tan(70) = 200/2.75 = 72.73 ft

A true dirtbag would have checked the corpse for usable gear before continuing with the climb.

According to the promulgators of steak and a blowjob day, serving one's man a steak and swallowing semen reduces a woman's chance of breast cancer by up to 50%