I don't see anyone really disagreeing with anyone else here, but confusion. You run your rope through a carabiner attached to pro and someone pitches, the pro experiences the force of the fall x the mech advantage of the simple pulley. In an ideal fbd this would be 2:1. As said before, there is flex in the rope, movement of the belayer, friction in the biner based on width etc. etc. to drop this force, but it is nevertheless multiplied. I believe Loren is saying if you use your belay anchor in this manner, as a directional, the belay anchor will be submitted to multiplied forces, just like anything else. There is simply no question in this.