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Ka for the weak acid, HA, is 4.7 x 10-7 at a certain temperature. Calculate the pH of a buffer solution made by mixing 67.2 mL of 0.138 M HA with 31.4 mL of 0.183 M NaA at this temperature. Assume that the volumes of the solutions are additive.

 

 

 

Anyone up to the challenge???????

 

C'mon, dont' be a wussy!

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Posted
Ka for the weak acid, HA, is 4.7 x 10-7 at a certain temperature. Calculate the pH of a buffer solution made by mixing 67.2 mL of 0.138 M HA with 31.4 mL of 0.183 M NaA at this temperature. Assume that the volumes of the solutions are additive.

 

Parden me for being a complete idiot....but what the hell does this mean?

Posted
Ka for the weak acid, HA, is 4.7 x 10-7 at a certain temperature. Calculate the pH of a buffer solution made by mixing 67.2 mL of 0.138 M HA with 31.4 mL of 0.183 M NaA at this temperature. Assume that the volumes of the solutions are additive.

 

Parden me for being a complete idiot....but what the hell does this mean?

 

 

No worries Kev, apparently I'm a complete idiot too! This whole problem means precisely this: only people with small penises and piercing reptilian eyes are good at chemistry problems! Those losers :nurd: .......

Posted

you know there are plenty of online calculators to do this problem for you. you'll never actually have to do this in the real world. i suggest you remind your chemistry prof of this.

Posted (edited)

We just finished pH of a buffer solution! Awesome dude!

 

After looking at it, can't you just use the henderson-hasselback equation: pH=-log(Ka)+log(base/acid)

Edited by kevino

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