EV Posted April 12, 2001 Share Posted April 12, 2001 Assuming a 200 pound climber, ten feet about his last placement, in the event of a fall, is there any way to determine what the force would be on the anchor in terms of kilo Newtons? I guess I'm looking for some mathematical equation. Thanks. Quote Link to comment Share on other sites More sharing options...
Alex Posted April 12, 2001 Share Posted April 12, 2001 Yes, it is a simple physics problem. I do not know the equation, but here are some conversion factors to start you off: 1 pound force = 4.45 newtons 1 newton = 0.225 pounds force 1 kilonewton = 225 pounds force You would also have to calculate acceleration due to gravity, and also how much energy is absorbed due to rope stretch. One key component is how much rope is actually payed out at the time of a fall, and what is the rope elongation? I remember Petzl publishing some pretty detailed information on this in of of their catalogues. Alex Quote Link to comment Share on other sites More sharing options...
erik Posted April 12, 2001 Share Posted April 12, 2001 look on petzl's website http://petzl.com/FRENG/tech/techframe.html they have a fall force calculator and all the math an aspiring math/physics dork could ever want. plus all sorts of other cool tech stuff. i learned i how lead real rock from this site and pics from a black diamond catalogue. Quote Link to comment Share on other sites More sharing options...
philfort Posted April 12, 2001 Share Posted April 12, 2001 Check out dbb's fall force calculator: http://students.washington.edu/dbb/index.html Quote Link to comment Share on other sites More sharing options...
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